Hacker Rank "CORE JAVA" - codes

                                               Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we'll work with the primitives used to hold integer values (byte, short, int, and long): A byte is an 8-bit signed integer. A short is a 16-bit signed integer. An int is a 32-bit signed integer. A long is a 64-bit signed integer. Given an input integer, you must determine which primitive data types are capable of properly storing that input. To get you started, a portion of the solution is provided for you in the editor. Reference:   https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html Input Format The first line contains an integer, , denoting the number of test cases. Each test case, , is comprised of a single line with an intege...

  Objective In this challenge, we're going to use loops to help us do some simple math. Task Given an integer, N, print its first 10 multiples. Each multiple   (where  ) should be printed on a new line in the form:  N x i = result . Input Format A single integer,  . Constraints 2<=N<=20 Output Format Print   lines of output; each line   (where  ) contains the   of   in the form: N x i = result . Sample Input 2 Sample Output 2 x 1 = 2 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18 2 x 10 = 20 JAVA CODE: This code will work for all the table just type the "N" value. import java . math .* ; import java . util .* ; class Solution { public static void main ( String [] args ) { Scanner in = new Scanner ( System . in ) ; int N = in . nextInt () ; if ( N >= 2 || N <= 20 ){ for ( int i = 1 ; i <= 10 ; i ++){ ...